2 log 1per243 ×5 log 1per125 ×3 log 1 per 16=
Matematika
qoniputrirahayu
Pertanyaan
2 log 1per243 ×5 log 1per125 ×3 log 1 per 16=
2 Jawaban
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1. Jawaban newwiguna
²log 1/243 x ⁵log 1/125 x ³log1/16
= ²log 1/243 x ³log1/16 x ⁵log 1/125
= ²log3⁻⁵ x ³log2⁻⁴ x ⁵log5⁻³
= (-5) x ²log3 x (-4) x ³log2 x (-3) x ⁵log5
= (-5) x (-4) x (-3) x ²log3 x ³log2 x ⁵log5
= - 60 x ²log2 x ⁵log5
= -60 x 1 x 1
= -60 -
2. Jawaban Brillianttt
Ingat sifat sifat dasar logaritma
bentuk pangkat ==> nᵃ = b
bentuk logaritma ==> ⁿlog b = a
1. ᵃlog a = 1
2. ᵃlog 1/n = ᵃlog n⁻¹
3. ᵃlog b . ᵇlog c = ᵃlog c
4. ᵃlog bⁿ = n x ᵃlog b
dsb.
maka
²log 1/243 x ⁵log 1/125 x ³log 1/16
= ²log 1/3⁵ x ⁵log 1/5³ x ³log 1/2⁴
= ²log 3⁻⁵ x ⁵log 5⁻³ x ³log 2⁻⁴
= (-5) ²log 3 x (-3) ⁵log 5 x (-4) ³log 2
= (-5)(-3)(-4) x ⁵log 5 x ²log 3 x ³log 2
= - 60 x 1 x ²log 2
= -60 x 1
= -60
Copast jawaban atas hehee..
Semoga membantu :)