Tinggi Tabung yg luas selimutnya 502,4cm kuadrat dan volumenya 2.512cmkubik adalah..... Cm

BANGUN RUANG
Tabung

Luas selimut = π×2r×t
502,4 = 3,14 × 2r × t
2rt = 502,4/3,14
2rt = 160

Volume = πr²t
2.512 = 3,14 × r²t
r²t = 2.512/3,14
r²t = 800

r²t / 2rt = 800/160
r×r×t / 2×r×t = 800/160 (corek-corek)
r/2 = 5
r = 2×5
r = 10 cm

2rt = 160
2×10×t = 160
20×t = 160
t = 160/20
t = 8 cm