suku banyak 4x³-x²+kx+2½ habis dibagi (2x+3) untuk k adalah

2x + 3 = 0
2x = -3
x = -3/2
f(-3/2) = 0
4(-3/2)³ - (-3/2)² + k(-3/2) + 2½ = 0
4(-27/8) - (9/4) - (3k/2) + 5/2 = 0
(-54/4) - (9/4) - (6k/4) + 10/4 = 0
(-54 - 9 - 6k + 10) / 4 = 0
- 53 - 6k = 0
-6k = 53
k = 53/6