tentukan rumus fungsi f(x), jika diketahui f(2x-3) = 2x^2-x+1

[tex]f(2x-3)=2x^2-x+1 \\ f(2x-3+3)=2(x+3)^2-(x+3)+1 \\ f(2x) = 2(x^2+6x+9)-x-3+1 \\ f(2x)=2x^2+12x+18-x-3+1 \\ f(2x) = 2x^2-11x+16 \\ f(2x:2)=2(\frac{x}{2})^2-11(\frac{x}{2})+16 \\ f(x)=2(\frac{x^2}{4})-11\frac{x}{2}+16 \\ f(x)=\frac{1}{2}(x^2)-\frac{11}{2}x+16[/tex]

misalkan
y=2x-3 maka x=y/2. + 3/2
f(y)=2(y/2. + 3/2)^2. - (y/2. + 3/2) + 1
= y^2. / 2. + 5y /2. + 4
maka f(x) = x^2. / 2. + 5x/2. + 4