-2^-2.a^-6.b^8/5^-2.a^10.b^12
Matematika
widiyul
Pertanyaan
-2^-2.a^-6.b^8/5^-2.a^10.b^12
1 Jawaban
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1. Jawaban ekacahyati
[(-2^-2 . a^-6 . b^8) / (5^-2 . a^10 . b^12)] = [(1/(-2)^2 : 1/(5)^2 . a^-16 . b^-4)] = 1/4 . 25/1 . a^-16 . b^-4 = 25/4 . a^-16 . b^-4