ke dalam 25 gr air dilarutkan 3 gr urea jika harga kf air 1,86. berapa titik bekunya

wp = 25 gram
wt = 3 gram (Mr = 60 gram/mol)
Kf = 1,86°C
Tf = .................?

ΔTf = wt/Mr x 1000/wp x Kf
= 3/60 x 1000/25 x 1,86
= 0,05 x 40 x 1,86
= 3,72°C

Tf = Tf° - ΔTf
= 0 - 3,72
= - 3,72°C