jarak pusat 2 ling A dan B 34 cm jari jari A =1 1/2 kali jari jari B jika GSPD + 16 hitunglah jari jari A dan B ?

GSPD² = AB² - ( R - r )²
16² = 34² - (3/2r + r)²
256 = 1156 - (3/2r + r)²
√900 = 3/2 r + r
30 x 2/5 = r
r = 12 cm 
34 = R + 12
R = 22 cm

Diketahui :
p = 34 cm
rA = 1 1/2 kali B atau 3/2B
d = 16 cm
Ditanyakan : rA dan rB
Penyelesaian :
[tex]d = \sqrt{p^{2}-(rA+rB)^{2}} [/tex]

[tex]d^{2} = p^{2}-(rA+rB)^{2}[/tex]

[tex]16^{2} = 34^{2}-(rA+rB)^{2}[/tex]

[tex]256 = 1156-(rA+rB)^{2}[/tex]

[tex]256 - 1156= -(rA+rB)^{2}[/tex]

[tex]-900= -(rA+rB)^{2}[/tex]  kalikan negatif maka :

[tex]900= (rA+rB)^{2}[/tex]

[tex](rA+rB) = \sqrt{900} [/tex]

[tex]rA+rB = 30[/tex]

Karena rA = 3/2B maka :
[tex]3/2rB+rB = 30[/tex]

[tex]rB+rB = \frac{30\times2}{3} [/tex]

[tex]2rB = \frac{60}{3} [/tex]

[tex]2rB = 20[/tex]

[tex]rB = 20/2[/tex]

[tex]rB = 10\,\, cm[/tex]

Karena jari-jari di B 10 cm maka jari-jari di A iala :
[tex]rA+rB = 30[/tex]

[tex]rA+10 = 30[/tex]

[tex]rA = 30 - 10[/tex]

[tex]rA = 20\,\,cm[/tex]


Maka Jari jari di A = 20 cm dan di B = 10 cm