tolong bantu jawab nomer 3 aja

[tex]x=1\rightarrow y^{2}=\sqrt{3-x}\rightarrow y=\sqrt[4]{3}[/tex]

[tex]y^{2}=\ln{\sqrt{3-x}}[/tex]
[tex]2y \frac{dy}{dx}=\frac{-\frac{1}{2}\frac{1}{\sqrt{3-x}}}{\sqrt{3-x}}[/tex]
[tex]2\sqrt[4]{3} \frac{dy}{dx}=\frac{-\frac{1}{2}\frac{1}{\sqrt{3-1}}}{\sqrt{3-1}}[/tex]
[tex]2\sqrt[4]{3} \frac{dy}{dx}=\frac{-\frac{1}{2\sqrt{2}}}{\sqrt{2}}[/tex]
[tex]2\sqrt[4]{3} \frac{dy}{dx}=-\frac{1}{4}[/tex]
[tex]\frac{dy}{dx}=-\frac{1}{8\sqrt[4]{3}}[/tex]