no 5 gimana yah! dan 6 juga gimana? no 6nya gk ada t gk ada r

Volume = 3850 dm
[tex]3850 = \frac{22}{7}*7^2*t [/tex]
[tex]t= \frac{3850}{ \frac{22}{7}*7^2 }=25dm [/tex]

25 - 5 = 20dm,,,  'tinggi air yg diarsir

[tex] \frac{22}{7}*7^2*20=3080dm^3[/tex]

V air yg diarsir = 3080 Liter

5. 2 × 22/7 × 7^2 × 5 = 1540
3850-1540 = 2310 dm^3

6. 942 × 2^2 = 3768 cm^3