Jika 9 log 4 = m, hasil 2 log 6 = . . .

^9log4=m,-> ^3²log2²-> 2/2.³log2-> ³log2= m
maka:
²log6= ²log(2×3)= ²log2+²log3
= 1 + 1/³log2
= 1+ 1/m
= (m+1)/m
semoga membantu!